Datasheet AP62600 (Diodes) - 21
| Hersteller | Diodes |
| Beschreibung | 4.5V To 18V Input, 6A Synchronous Buck Converter |
| Seiten / Seite | 26 / 21 — AP62600. Application Information. Inductor. Eq. 9. Eq. 10. www.diodes.com |
| Dateiformat / Größe | PDF / 1.9 Mb |
| Dokumentensprache | Englisch |
AP62600. Application Information. Inductor. Eq. 9. Eq. 10. www.diodes.com

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Textversion des Dokuments
AP62600 Application Information
(cont.)
12 Inductor
Calculating the inductor value is a critical factor in designing a buck converter. For most designs, the following equation can be used to calculate the inductor value:
Eq. 9
Where: ∆IL is the inductor current ripple fSW is the buck converter switching frequency For AP62600, choose ∆IL to be 30% to 50% of the maximum load current of 6A. The inductor peak current is calculated by:
Eq. 10
Peak current determines the required saturation current rating, which influences the size of the inductor. Saturating the inductor decreases the converter efficiency while increasing the temperatures of the inductor and the internal power MOSFETs. Therefore, choosing an inductor with the appropriate saturation current rating is important. For most applications, it is recommended to select an inductor of approximately 0.47µH to 4.7µH with a DC current rating of at least 35% higher than the maximum load current. For highest efficiency, the inductor’s DC resistance should be less than 10mΩ. Use a larger inductance for improved efficiency under light load conditions. AP62600 21 of 26 January 2020 Document number: DS42003 Rev. 2 - 2
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